find the percentage of reduction in surface area
Q.6. Three solid metal spheres of radii 3 cm, 4 cm and 5 cm respectively are melted together. The obtained metal is recast into a single solid sphere. The percentage reduction in the surface area of the solid sphere is
A. 24 %
B. 26 %
C. 28 %
D. 30 %
Dear Student,
Please find below the solution to the asked query:
We know : Surface area of sphere = 4 r2
So,
Surface area of sphere with radius 3 cm = 4 ( 3 )2 = 36 cm2 ,
Surface area of sphere with radius 4 cm = 4 ( 4 )2 = 64 cm2
And
Surface area of sphere with radius 5 cm = 4 ( 5 )2 = 100 cm2
Then,
Total surface area of all three spheres = 36 + 64 + 100 = 200 cm2
We know volume of sphere = r3
As given : Three solid metal spheres of radii 3 cm, 4 cm and 5 cm respectively are melted together. The obtained metal is recast into a single solid sphere. So
Volume of all three sphere = Volume of new sphere
We assume radius of new sphere = r , So
( 3 )3 + ( 4 )3 + ( 5 )3 = r3 ,
[ ( 3 )3 + ( 4 )3 + ( 5 )3 ] = r3 ,
[ 27 + 64 + 125 ] = r3 ,
[216 ] = r3 ,
r = 6 cm
Then,
Surface area of new sphere = 4 ( 6 )2 = 144 cm2
Change in surface area = 200 - 144 = 56 cm2
Thus ,
Percentage reduction in the surface area of the solid sphere =
Therefore,
Option ( C ) ( Ans )
Hope this information will clear your doubts about topic.
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Please find below the solution to the asked query:
We know : Surface area of sphere = 4 r2
So,
Surface area of sphere with radius 3 cm = 4 ( 3 )2 = 36 cm2 ,
Surface area of sphere with radius 4 cm = 4 ( 4 )2 = 64 cm2
And
Surface area of sphere with radius 5 cm = 4 ( 5 )2 = 100 cm2
Then,
Total surface area of all three spheres = 36 + 64 + 100 = 200 cm2
We know volume of sphere = r3
As given : Three solid metal spheres of radii 3 cm, 4 cm and 5 cm respectively are melted together. The obtained metal is recast into a single solid sphere. So
Volume of all three sphere = Volume of new sphere
We assume radius of new sphere = r , So
( 3 )3 + ( 4 )3 + ( 5 )3 = r3 ,
[ ( 3 )3 + ( 4 )3 + ( 5 )3 ] = r3 ,
[ 27 + 64 + 125 ] = r3 ,
[216 ] = r3 ,
r = 6 cm
Then,
Surface area of new sphere = 4 ( 6 )2 = 144 cm2
Change in surface area = 200 - 144 = 56 cm2
Thus ,
Percentage reduction in the surface area of the solid sphere =
Therefore,
Option ( C ) ( Ans )
Hope this information will clear your doubts about topic.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards