Find the range of f(x)=cos[x],for x lies between -pi/2 to pi/2 Thanks for giving answer to my query but Iwould - Maths - Relations and Functions

Question

Find the range of f(x)=cos[x],for x lies between -pi/2
to pi/2
Thanks for giving answer to my query but Iwould like to
inform that I am not able to understand the solution pls explain it
in detail
solution given by you earlier
The given function is f(x)=cos[x],for -pi/2Since the angle is
[x] so the interval -pi/2 1 -pi/2 2 -1 3 0 4 1 In the interval
-pi/2 So, cos [x] = cos(-2) = cos 2In the interval -1 So, cos [x] =
cos(-1) = cos 1In the interval 0 So, cos [x] = cos0 = 1In the
interval 1 So, cos [x] = cos1Thus, the range of f(x) = cos[x], for
-pi/2

Duke Biswass · Accepted Answer

f(x)=cos(x) for x varying between $- \frac{π}{2}$ to $\frac{π}{2}$ the value of cos(x) becomes from 0 to 1 hence range of f(x) for x varying from $- \frac{π}{2}$ to $\frac{π}{2}$ is [0,1]