Find the ratio in which line segment joining the points (2,-3) and (3,1) is divided by x-axis . Share with your friends Share 0 Lovina Kansal answered this Dear student A2,-3,B(3,1)let the coordinate of point of division be (x,0)Let the ratio be m:nThe required coordinate =3m+2nm+n,m-3nm+nGiven the y-coordinate=0 (since it cuts the x-axis)Therefore, m-3nm+n=0⇒m=3n⇒mn=31So, the required ratio is 3:1 Regards 0 View Full Answer Shivam Ranjan Sinha answered this 3:1 2 Mohnishh answered this From the above question Let the required ratio be k:1 i.e m:n Since the line devides the x axis (x,0) Therefore A(x,0) ; B(2,-3) ; C(3,-1) On using section formula y = my2+ny1/m+n On replacing values 0 = k X 1 + 1 X -3 / k + 1 0 = k - 3 / k + 1 0 = k - 3 k = 3 Hence the required ratio is 3:1 2
