Find the square of. a+1/5a

Dear student,

A s s u m i n g t h e q u e s t i o n i s {(a + \frac{1}{5 a})}^{2} = a^{2} + {(\frac{1}{5 a})}^{2} + 2 \times a \times \frac{1}{5 a} - - [u \sin g {(a + b)}^{2} = a^{2} + b^{2} + 2 a b] = a^{2} + \frac{1}{25 a^{2}} + \frac{2}{5}

Regards