find the square root of complex number 2 + 2√3 i Share with your friends Share 0 Rishabh Mittal answered this Dear Student, Let x+iy=2+23iSquaring on both sides, we getx+iy2 = 2+23ix2+i2y2 +i2xy = 2+23ix2-y2 + i2xy = 2 +23iOn comparing both sides, we getx2-y2=2 ... i2xy = 23 ... iiWe know,x2+y22=x2-y22+4x2y2x2+y22=22 + 232x2+y22=4+12x2+y22=16x2+y2=4 ... iiiAdding i and iii2x2 = 6x2=3x=±3Substituting the value of x in ii, we get2±3y=23y=±1So, square root of 2+23i is ±3 ± i Regards -1 View Full Answer