# Find the sum of deviations of the variate values 3, 4, 6, 7, 8, 14 fromtheir mean.

Oh, you didn't ask for average deviation, sorry. Sum of deviations on taking modulus is 2.5x6 = 15.

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Their mean is (3+4+6+7+8+14)/6 = 7

Sum of deviations, without taking modulus, is obviously zero. But for actual mean deviation from the value, [(7-3) + (7-4) + (7-7) + (8-7) + (14-7)]/6 = 5/2

So on average the variates deviate by 2.5

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hey i have not given you the thumbs down..

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hey i have not given you the thumbs down..

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Yes, as I mentioned, sum of deviations without the modulus is clearly zero; else it would contradict the law of averages (you can refer to the topic in wikipedia 'law of averages').

It's alright, the thumbs ups and downs don't really matter. If you found the answer satisfactory, you give me an up - if not, you can give a thumbs down too :) The fact of the matter is, you should be able to understand my answer, and if not, my job is poorly done!

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https://youtu.be/LcCFhISx3QY
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Concern the link which i have given.
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Hope this helps • -1
ans = 0
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0021
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0007
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The variate values are:

3, 4, 6, 7, 8, 14

Mean is given by:  Thus, .

Now,      Sum of deviations of the variate values= = Therefore, the sum of deviations of the variate values is 1

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