Find the total area of 12squares whose sides are 12cm,13cm,...,23cm respectively
Dear Student,
Please find the below required solution.
Given that the side of 12 square are 12, 13, 14, 15, ... , 23 (in cm)
And area of square = (side)2
So area of 12 square whose sides are 12, 13, ......, 23 (in cm) is 122, 132, 142, ......, 232 (in cm2)
Hence total area of 12 square = 122+132+142+ ......, +232
= (12+22+32+....112+122+132+142+ ......, +232)-(12+22+32+....112)
= (12+22+32+ ......, +232)-(12+22+32+....112)
= [23(23+1)(23x2+1)]/6 - [11(11+1)(11x2+1)]/6 [ using sum of square of natural number = n(n +1)(2n+1)/6 ]
= [23x24x47]/6-[11x12x23]/6
= 4324-506 = 3818 cm2
Hence total area of 12 square is 3818 cm2
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Please find the below required solution.
Given that the side of 12 square are 12, 13, 14, 15, ... , 23 (in cm)
And area of square = (side)2
So area of 12 square whose sides are 12, 13, ......, 23 (in cm) is 122, 132, 142, ......, 232 (in cm2)
Hence total area of 12 square = 122+132+142+ ......, +232
= (12+22+32+....112+122+132+142+ ......, +232)-(12+22+32+....112)
= (12+22+32+ ......, +232)-(12+22+32+....112)
= [23(23+1)(23x2+1)]/6 - [11(11+1)(11x2+1)]/6 [ using sum of square of natural number = n(n +1)(2n+1)/6 ]
= [23x24x47]/6-[11x12x23]/6
= 4324-506 = 3818 cm2
Hence total area of 12 square is 3818 cm2
Hope this information will clear your doubts about given problem.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards