find the value of cot (-600 deg.)

cot -600° = - cot 600°   as cot -θ = - cot θ= - cot 540° + 60°= - cot 3π + π3    as 180° = π radiansClearly 600° is in the third quadrant and cot θ is positive in third quadrant.Hence, - cot 3π + π3 = - cot π3    as cot 3π + θ = cot θ                                   = - 13

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