Dear Student, PP5×QQ2Q25+2Q250 2 5 5 7 5since Q+2=5⇒ Q=5-2⇒Q=3PP5×332325+23250 2 5 5 7 5From multiplication above3×5=15, so we get 5 from here and 1 carrynow 3×P+1=2 Or 12 or 22now 3p+1=2⇒3p=1hence p=13 which is not possible as P is an integersimilarly for 3p+1=12, we get p=113but 3p+1=22we get p=213=7Hence p=7so answer is p=7, and q=3 Regards,

Find value of pandq

Find value of pandq Of a number is 189.—What of the number? 315 c. 540 •nd Q represents thé' prime digits. then find the value of P •nd Q 7.3 3 Of the following figures satisfy the given conditions? Faces : 4 Edges : 6 Vertices : 4 Faces : S Edges : 9 Vertices : 6

Dear Student,

P P 5 \times Q Q 2 Q 25 + 2 Q 250 2 5 5 7 5 \sin c e Q + 2 = 5 \Rightarrow Q = 5 - 2 \Rightarrow Q = 3 P P 5 \times 33 2325 + 23250 2 5 5 7 5 F r o m m u l t i p l i c a t i o n a b o v e 3 \times 5 = 15, s o w e g e t 5 f r o m h e r e a n d 1 c a r r y n o w 3 \times P + 1 = 2 O r 12 o r 22 n o w 3 p + 1 = 2 \Rightarrow 3 p = 1 h e n c e p = \frac{1}{3} w h i c h i s n o t p o s s i b l e a s P i s a n i n t e g e r s i m i l a r l y f o r 3 p + 1 = 12, w e g e t p = \frac{11}{3} b u t 3 p + 1 = 22 w e g e t p = \frac{21}{3} = 7 H e n c e p = 7 s o a n s w e r i s p = 7, a n d q = 3

Regards,

View Full Answer

Find value of pandq Find value of pandq Of a number is 189.—What of the number? 315 c. 540 •nd Q represents thé' prime digits. then find the value of P •nd Q 7.3 3 Of the following figures satisfy the given conditions? Faces : 4 Edges : 6 Vertices : 4 Faces : S Edges : 9 Vertices : 6

Find value of pandq

Find value of pandq Of a number is 189.—What of the number? 315 c. 540 •nd Q represents thé' prime digits. then find the value of P •nd Q 7.3 3 Of the following figures satisfy the given conditions? Faces : 4 Edges : 6 Vertices : 4 Faces : S Edges : 9 Vertices : 6