Find zeroesof: x2+2root2x-6 ,t2-3 Share with your friends Share 0 Varun.Rawat answered this 1.Let px = x2+22x-6Now, zeroes of px are given by solving the equation,px = 0⇒x2+22x-6 = 0⇒x2 + 32x - 2x - 6 = 0⇒xx+32 - 2x+32 = 0⇒x-2x+32 = 0⇒x= 2 or x = -322.Let pt = t2-3Now, zeroes of pt are given by solving the equation,pt = 0⇒t2 - 3 = 0⇒t2 - 32 = 0⇒t+3t-3 = 0⇒t = -3 or t = 3 -3 View Full Answer
