FINT THE SIDE OF THE SQUARE IF ITS AREA IS (4A2 -12AB+9B2) 2. THE PRODUCT OF TWO NUMBERS IS (X2 -13X+40)... IF ONE OF THEM IS (X-5), FIND THE OTHER

Area = 4a2 - 12 ab +9b​2
=(2a)2 - 2 (2a)(3b) + (3b)2
=(2a - 3b)2
= ​(2a - 3b) +​(2a - 3b)

We know, Area of square = Side$×$
Side

Thus, Side of square = (2a - 3b)

• 3
area = 4a2 - 12 ab +9b​2
=(2a)2 - 2 (2a)(3b) + (3b)2
=(2a - 3b)2
= ​(2a - 3b) +​(2a - 3b)
• 1
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