For two reactions in equilibrium in same container 1. A (s) ------> 2B (g) + C (g) ( Kp)1 = 4atm 2. D(s) ------> B (g) + E (g) ( Kp)2 = 1atm Pressure of B ( g ) at equilibrium will be? ( Ans is 3 atm, but how?) Share with your friends Share 7 Avni answered this Kp1 = PB2 PC=4 PB=4PC=21PC Kp2= PB PE=1 PB=1PE The equations cannot be solved further, some data is missing. -59 View Full Answer