For two reactions in equilibrium in same container 1. A (s) ------> 2B (g) + C (g) ( Kp)1 = 4atm 2. D(s) ------> B (g) + E (g) ( Kp)2 = 1atm Pressure of B ( g ) at equilibrium will be? ( Ans is 3 atm, but how?)

Kp1 = PB2 PC=4
PB=4PC=21PC

Kp2PB PE=1
PB=1PE

The equations cannot be solved further, some data is missing. 
 

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