From a point in the interior of an equilateral triangle,perpendiculars are drawn on three sides.The length of perpendiculars are 14 cm,10 cm and 6 cm.Find the area of the triangle.
Here is the solution to your question-
∆ABC is an equilateral triangle.
Let the side of the equilateral ∆ABC be a cm.
P is a point in the interior of the ∆ABC. PQ⊥BC, PR⊥CA and PS⊥AB
Let PS = 14 cm, PQ = 10 cm and PR = 6 cm
Area of ∆ABC = Area of ∆APB + Area of ∆BPC + Area of ∆CPA