from a station x a train starts from rest and attains a speed of 54km/h in 10s,then with this uniform - Science - Force and Laws of Motion

Question

from a station x a train starts from rest and attains a speed of
54km/h in 10s,then with this uniform speed it moves for 8 min and
then by applying brakes it stops at station y in 6s find the
distance between station x and y?

Pratyay Ghosh · Accepted Answer

First part of the motion,
u=0v=54 km/h=15 m/st=10 s
The acceleration,
v=u+at⇒a=vt=1510=1 5 m/s2
The distance travelled,
s1=ut+12at2⇒s1=12×1 5×102=75 m
In the second part,
t=8 min
the distance travelled,
s2=vt=15×8×60=7200 m
In the last part,
u=15 m/sv=0t=6 s
The deceleration,
v=u-at⇒a=ut=15/6=2 5 m/s2
Distance travelled
v2=u2-2as⇒s3=u22a=1522×2 5=45 m
Distance between x and y=s1+s2+s3=75+7200+45=7320 m=7
32 km

from a station x a train starts from rest and attains a speed of 54km/h in 10s,then with this uniform speed it moves for 8 min and then by applying brakes it stops at station y in 6s . find the distance between station x and y?