From a well shuffled pack of 52 cards, two black kings and two black jacks are removed From the remaining - Maths - Probability

Question

From a well shuffled pack of 52 cards, two black kings and two
black jacks are removed From the remaining cards a is drawn at
random Find the probability that drawn card is neither an ace nor a
king

Ayush Jha · Accepted Answer

Since 4 cards are removed from the stuff.

So the total number of cards = 48.

Since 2 black kings are removed.

So number of cards left in the stuff which are either ace or king = 6

So,

$P (a c e o r k i n g) = \frac{6}{48} = \frac{1}{8}$

So,

$P (n o t g e t t i n g a c e o r k i n g) = 1 - \frac{1}{8} = \frac{7}{8}$

From a well shuffled pack of 52 cards, two black kings and two black jacks are removed.From the remaining cards a is drawn at random.Find the probability that drawn card is neither an ace nor a king.