From the top of 100 m high, the angles of depression of the top and the bottom of a tower - Maths - Some Applications of Trigonometry

Question

​From the top of 100 m high, the angles of depression of the
top and the bottom of a tower are observed to be 45 and 60 degree
respectively Find the height of the tower Also find the distance
between the foot of the building and the bottom of the tower
And plzz do not send the any link give solution

Varun Rawat · Accepted Answer

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Let AB be the building and CD be the tower
Let CD = h mts Draw CL⊥AB
Now, LB = CD = h and LC = BD
Let ∠ACL = 45°; ∠ADB = 60°In ∆ALC,tan 45° = ALLC⇒1 = 100-hLC⇒LC = 100 - h   
1In ∆ABD,tan 60° = ABBD⇒3 = 100LC⇒LC = 1003     
2From 1 and 2, we get100 - h = 1003⇒1003 - 3h = 100⇒h = 1003 - 1003 = 1003 - 1003×33 = 300-10033 mSo, height of tower =  300-10033 mDistance between building and tower = 1003 = 10033 m