Given: a, b are positive intergers and a^3*b^2=72. Find -2a+3b

Dear student
We have,a3b2=72a3b2=2×2×2×3×3a3b2=23×32On comparing, we geta=2 and b=3So, -2a+3b=-2(2)+3(3)=-4+9=5
Regards

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