Given that A union B = C and A intersecting B = null set,
Prove :- C -B =A

Given,AB=AB'=A...(i)Now,AB=CTaking intersection with B' on both sides,(AB)B'=CB'(AB')(BB')=CB'A=CB' ...[From (i)]CB'=A...(ii)Now,C-B=CB'=A...[From (ii)]

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