How can we draw a right angled triangle having hypotenuse of length 6.4 cm and one of the acute angle as 40 degree ?
in the right angled triangle one acute angle is 40 deg.
therefore other angle = 90-40 = 50 deg
draw a line segment AB = 6.4 cm.
at A draw an angle of 40 deg and at B draw an angle of 50 deg.
let it intersect at C.
thus ACB is a right angled triangle , right angled at C.
and hypotenuse AB = 6.4 cm
hope this helps you.