How do we know the hybridisation in solid state as in these examples where the molecules undergo ionisation - Chemistry - Chemical Bonding and Molecular Structure

Question

How do we know the hybridisation in solid state as in these
examples where the molecules undergo ionisation ? Is there any way
by which we can know the radicals of the molecules after ionisation
without mugging up ? Why PF5 doesnot undergo ionisation as shown

Monalisa Behera · Accepted Answer

Dear Student,

PF5 exists in ionic state in solids The reason being that it does
not exists simply as a PF5 molecule Rather it forms two complex
compounds:-
1 PF4+
2 PF6-
So it exists as an ionic compound with formula [PF4]+[PF6]-

In polar solvents, PF5 undergoes autoionization
According to Dilute solutions dissociate

PF5 â‡Œ [PF4 ]+ F− (tetrahedral)

At higher concentrations, a second equilibrium becomes more
prevalent,

2 PF5 â‡Œ [PF4 ] + and ( [PF6 ] -
octahedral)

Regards,