how many ATP are formed during glycolysis?

glycolysis only gives 4 but it costs two so only a net profit of two. Respiration of glucose, which I think is what you mean, gives between 36 and 38 depending on where the glucose is broken down. The liver is much better at it then other cells so it can get 38 while most cells only get 36.
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The pathway of glycolysis can be seen as consisting of 2 separate phases. The first is the chemical priming phase requiring energy in the form of ATP, and the second is considered the energy-yielding phase. In the first phase, 2 equivalents of ATP are used to convert glucose to fructose 1,6-bisphosphate (F1,6BP). In the second phase F1,6BP is degraded to pyruvate, with the production of 4 equivalents of ATP and 2 equivalents of NADH.

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Total ATP produced during glycolysis=1  NADH2  =3ATP molecules  (In the formation of 1.3-diphosphoglyceric acid +  

                                                                   1 ATP     (In forming 3 phosphoglyceric acid)           +

                                                                   1 ATP   (In forming Pyruvic acid-last step)       ===5 ATP

From 2 pyruvic acid molecules ==10 ATP

Total AtP consumed in this process=1ATP   (in forming Glucose-6-phosphate)  + 1 ATP (in forming Fructose 1,6 diphosphate) ===2 ATP

Therefore net gain ===10-2=8ATP

                                                                   

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if we say just during glycolysis then ans. will be 4 atp's but if we say during complete process of cellular respiration then ETS will be included so then we have to count the no. of  atp's formed by nadh2 also.so then ans. will be 4+6 =10 atp molecules

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during glycolysis 4 ATP are formed by substrate level phsphorylation and from which 2 ATP are used in the glycolysis itself

hence total atp formed are 2ATP

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During glycolysis 4 ATP are produced out of which 2 ATP are taken from the cell.Therefore ,net ATP =4-2=2.And 2NADH are produced.1NADH contain 3 ATP molecules.In 2NADH 6ATP molecules are produced
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4 ATP
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