how many electrons protons and neutrons are present in 207Pb82.write its electronic configuration. how many Valence Electrons does it have ?what will be its valency? Share with your friends Share 0 Vartika Jain answered this Dear Student, For 20782Pb, No. of electrons = No. of protons = Atomic number=82Number of neutrons = Mass number - Atomic number =207-82 =125Its electronic configuration will be [Xe] 4f14 5d10 6s2 6p2Number of valence electrons =4Its valency is 2. -2 View Full Answer