how many electrons protons and neutrons are present in 207Pb82.write its electronic configuration. how many Valence Electrons does it have ?what will be its valency?

Dear Student,


For 20782Pb, No. of electrons = No. of protons = Atomic number=82Number of neutrons = Mass number - Atomic number                                     =207-82                                     =125Its electronic configuration will be [Xe] 4f14 5d10 6s2 6p2Number of valence electrons =4Its valency is 2. 

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