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how many equational divisions are necessary in a cell of onion root tip to form  128 cells ?  1)64  2)128   3)7  4)127  Explain with details  plzzz its urgent

Dear Student,

The number of equatorial divisions necessary in a cell of onion root tip to form 128 cells is 64.

There is a formula to calculate this. Since this type of division results in two daughter cells from single parent cell.

So, the formula is 2n, here n represents number of divisions.

Thus the answer to the question can be calculated as:

2n= 264= 128.

64 divisions are necessary to get 128 cells.

Hope this answer helps,

Cheers!!

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Ma'am isn't it 2n and not 2n ?? 264  is a very large number. So the correct formula is 2n

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onion root tip follows mitotic divison(2n)....1 cell divi. into 2 (think lorgical uwill get)

Mitosis:
1 cell (2n2c) replicates DNA to become (2n4c). Chromosomes align and split at their centromeres, and cell cleavage results in 2 cells (2n2c).

Meiosis:
1 cell (2n2c) replicates DNA to become (2n4c). First meiotic division results in 2 cells (1n2c) called a reduction division because homologous chromosome pairs separate rather than splitting sister chromatids. 2 cells (1n2c) undergo second meiotic division resulting in 4 cells (1n1c).

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