how many moles are present in 9g of water

 9 g H2O) / (18.0153 g H2O/mol) = 0.5 mole

  • 1

given weight=9g                                                                                                                                                                            molecular weight = 2+16= 18g                                                                                                                                                  by using formmula,   no. of moles= given weight divided by molecular weight                                                          9/18= 0.5 mole

  • 9

Water(H2O) has a molecuar mass of 18, this means it weights 18 g per mole. A mole is 6.0221415*1023molecules (Avogadro's number). If you have 1 g of water, you therefore have 1/18 of a mole, or 3.34*1022 molecules.

and in 9 gm of water you have 9/18 of mole or 3.011*1023  molecules

  • 4

mlecular mass of water = 1*2+16 =18                                                        (H=1g,O=16)          

18g=1mole

9g=9/18mole=0.5mole

9g of water contain 0.5 mole

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