How many Oxygen, Hydrogen and Carbon atoms does 12 g of Citral ( C₁₀ H₁₆O ) contains ?

Dear Student,

The formula of Citral is C₁₀H₁₆O. The given mass is 12 g.
The molar mass of citral is = 10 x 12 + 16 x 1 + 16 = 152 g mol^-1

Thus, the number of moles of citral = $\frac{12}{152}=0.079 mol$

From the formula, we can see that one mole of citral contains 10N_A atoms of carbon, 16N_A atoms of hydrogen, and N_A atoms of oxygen, where N_A is Avogadro's number.

Thus, 0.079 mol of citral contains:
$$\begin{gathered} Carbon atoms = 0.079 \times 10\times 6.022 \times {10}^{23}= 4.75 \times {10}^{23} atoms \\ Hydrogen atoms = 0.079 \times 16 \times 6.022 \times {10}^{23}=7.61 \times {10}^{23 }atoms \\ Oxygen atoms = 0.079 \times 6.022 \times {10}^{23}=4.75 \times {10}^{22} atoms \end{gathered}$$ 



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