How this step was done

Dear Student,

In the question, the term $\frac{k}{3}+1=\frac{k+3}{3}$ has been done by taking 3 as the LCM of $\frac{k}{3}$ and 1.

Regards

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It is very simple, if you look carefully there is a common factor

(k+1)(k+2) has been taken as common factor out of the equation that result to (k+1)(k+2) (k/3+1) where "1" is placed to complete the new equation.
• 0
It is very simple, if you look carefully there is a common factor

(k+1)(k+2) has been taken as common factor out of the equation that result to (k+1)(k+2) (k/3+1) where "1" is placed to complete the new equation.......
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What are you looking for?