how to find focus of parabola in the question ;-

Find the area bounded by the parabolay 2= 16x and its latus rectum.


The equation of latus rectum is x = aSo for y2=16x,  a =4So intersection point of x = 4 and y2=16x is, y = ±8So coordinate of L is 4,8.Now area of OSL is, =04ydx=044xdx=83×x3204=643Now using symmetry area of OSL' will be same so area of LOL' =2×643 =1283 square unit
 

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