how to find the measure of the height of the image formed on a concave mirror?

Dear student,
$$\begin{gathered} We can find tje image height by u\sin g the formula, \\ m=\frac{h_i}{h_o} \\ Here m=magnification \\ {h}_i=height of the image \\ {h}_o=height of the object \end{gathered}$$
Points to remember:-
The positive magnitude of magnification indicates virtual and erect image.
The negative magnitude of magnification indicates real and inverted image

As the object is always above the principal axis, the height of the object is always positive. But sign for image height may vary according to the type of image formed. The height of virtual images should be taken positive while the height of real images should be taken negative


Hope this information will clear your doubts about topic.

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