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Class-8»Maths

How to solve the following

y-(y-1)/2=1-(y-2)/3

y - \frac{y - 1}{2} = 1 - \frac{y - 2}{3} \frac{2 y - y + 1}{2} = \frac{3 - y + 2}{3} or \frac{y + 1}{2} = \frac{5 - y}{3} 3 y + 3 = 10 - 2 y 5 y = 7 or y = \frac{7}{5}

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