How to subtract the expressions 1) (4xy - 3xy) ; (3xy - 16z) 2) (5x + 4y + 7z) - Maths - Algebraic Expessions and Operations on them

Question

How to subtract the expressions
1) (4xy - 3xy) ; (3xy - 16z)
2) (5x + 4y + 7z) ; (x + 2y + 3z)
3) (14x^2 + 8xy + 3y) ; ( 26x^2 - 8xy - 17y2)
4) (6x^2 + 7xy + 16y^2) ; (16x^2 - 17xy)
5) (4x + 16z) ; (19y - 14z + 16x)

Deepak Kumar · Accepted Answer

Dear Student , (1) (4xy-3xy);(3xy-16z)As you have not given in the question clearly so i am subtracting (4xy-3xy)-(3xy-16z)4xy-3xy-3xy+16z                                because (+)×(-)=(-) Also  (-)×(-)=(+)-2xy+16z    AnsKindly post different query in separate threads Regards

How to subtract the expressions. 1) (4xy - 3xy) ; (3xy - 16z) 2) (5x + 4y + 7z) ; (x + 2y + 3z) 3) (14x^2 + 8xy + 3y) ; ( 26x^2 - 8xy - 17y2) 4) (6x^2 + 7xy + 16y^2) ; (16x^2 - 17xy) 5) (4x + 16z) ; (19y - 14z + 16x)

How to subtract the expressions.
1) (4xy - 3xy) ; (3xy - 16z)
2) (5x + 4y + 7z) ; (x + 2y + 3z)
3) (14x^2 + 8xy + 3y) ; ( 26x^2 - 8xy - 17y2)
4) (6x^2 + 7xy + 16y^2) ; (16x^2 - 17xy)
5) (4x + 16z) ; (19y - 14z + 16x)