Hurry tell this ques by writing all statements solve all

Dear student
1+xn=C0+C1x+C2x2+...+Cnxn    ...(1)x+1n=C0xn+C1xn-1+C2xn-2+...+Cn      ...(2)Multiplying (1) and (2), we getC0+C1x+C2x2+...+CnxnC0xn+C1xn-1+C2xn-2+...+Cn=1+x2nComparing the coefficient of xnC02+C12+C22+...+Cn2=2nCnFrom the product of (1) and (2) comparing coefficients of xn-2  both sides,C0C2+C1C3+...+Cn-2Cn=2nCn-2
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