I am again sending this question as I didn't get answer to the same in the 1st case.
So, I sincerely request the experts to find all the angles in the above figure according to all the conditions or circumstances given. 

Dear student
Since COE and BOG are consecutive  multiples of 10°So, Let COE=10x and BOG=10x+10°Since OA bisects BOGAOB=AOG=12BOG=5x+5°Since OD bisects COECOD=DOE=12COE=5xGiven: BOC=COD4+90°=5x4+90°Since GEis a straight lineBOG+BOC+COE=180°10x+10°+5x4+90°+10x=180°20x+5x4=80°80x+5x=320°85x=320°x=32085°x=6417°So,COE=10x=64017°BOG=10x+10=64017°+10°=81017°COD=DOE=12COE=6402×17=32017°AOB=AOG=12BOG=8102×17=40517°BOC=5x4+90°=54×6417°+90°=8017°+90°=161017°GOF=3BOG=3×81017°=243017°
and ,EOF=180°-GOF    {linear pair]EOF=180°-243017°=63017°
Regards

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