I bymistake, sent 2 same questions, but in the 1st question itself I was told that it was missing the value of one angle by Neha Sethi ma'am. I rechecked it and posted it again as I was asked. But, then also I did not get the answer. This time please answer it here or in the old ones. Please Neha Sethi ma'am. Share with your friends Share 0 Shruti Tyagi answered this Dear Student, since OA bisects ∠BOGlet ∠BOG= 2ythen ∠BOA=∠AOG=ysimilarly let ∠COE=2xthen ∠COD=∠DOW=xsince EOG is straight line∠FOG+∠FOE=1803×2y+70=1806y=110y=1106y=553° Also ∠BOG+∠BOC+∠COE=1802y+x+90+2x=1802y+3x=901103+3x=903x=90-1103x=30-1109x=270-1109x=1609hence value of angles are∠AOG=∠AOB=y=553° ∠BOC=x+90=17.77+90=107.77∠COD=∠DOE=x=1609∠FOG=6y=110∠FOE=70 Regards, -1 View Full Answer