# I had asked that how: (-)(-)= (+). I saw that in that, (-) (+) = (-)... Prove how(-) (+) = (-)

We know that –ab is a unique solution to the equation x + ab = 0, therefore it is sufficient to show that

ab + (-a)b = 0

But

ab + (-a)b = (a + (-a))b

by the Distributive Property of Real Numbers (Axiom 5A) and

a + (-a) = 0

by Axiom 5A (the existence of Additive Identity).

Therefore,

ab + (-a)b = (a + (-a))b = 0b = 0

and we are done.

The theorem above give to 2 corollaries.

Corollary 1

For any number b, (-1)b = –b.

If we take a = -1, then (-1)b = – (1b) = –b by the existence of multiplicative identity (Axiom 5M).

Corollary 2

(-1)(-1) = 1

â€‹Regards
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