I have said many times that "DO NOT SEND SIMILAR QUERIES BECAUSE LINK COULD NOT BE OPENED DUE TO SOME TECHNICAL PROBLEM".So Expert Ashutosh kindly do not send link.?
-Repeating the question:-?
Q.3. Find the values of
(i) $\frac{\sin 60°}{{\cos }^2 45°}-3\tan 30°+5\cos 90°$

Dear Student,

Please find below the solution to the asked query:

We take given equation and substitute trigonometric values :

$$\begin{gathered} \frac{\mathrm{Sin} 60° }{{\mathrm{Cos}}^2 45° }- 3 \tan 30° +5 \mathrm{Cos} 90° \\ \mathrm{We} \mathrm{know} : \mathrm{Sin} 60° =\frac{\sqrt{3}}{2} , \mathrm{Cos} 45° = \frac{1}{\sqrt{2}} , \tan 30° =\frac{1}{\sqrt{3}} \mathrm{and} \mathrm{Cos} 90° =0 , \mathrm{So} \\ \Rightarrow \frac{{\displaystyle \frac{\sqrt{3}}{2}} }{{\left({\displaystyle \frac{1}{\sqrt{2}}} \right)}^2}- 3 \times \frac{1}{\sqrt{3}} +5 \times 0 \\ \Rightarrow \frac{{\displaystyle \frac{\sqrt{3}}{2} }}{{\displaystyle \frac{1}{2}}}- \frac{3}{\sqrt{3}} + 0 \\ \Rightarrow \frac{\sqrt{3}}{2}\times \frac{{\displaystyle 2 }}{{\displaystyle 1}}- \frac{3}{\sqrt{3}} \\ \Rightarrow \sqrt{3}- \frac{3}{\sqrt{3}} \\ \Rightarrow \frac{3 - 3}{\sqrt{3}} \\ \Rightarrow \frac{0}{\sqrt{3}} \\ \mathbf{\Rightarrow }\mathbf{0}\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{ }\mathbf{(}\mathbf{ }\mathbf{ }\mathbf{Ans}\mathbf{ }\mathbf{)} \end{gathered}$$
Therefore,

L.H.S. = R.H.S.                                       ( Hence proved )


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