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$$\begin{gathered} As the generation time is 50 minutes . \\ It takes 50 minutes to double the bacterium , given culture contains {10}^8 cells per mL. \\ Thus number of cells after 300 minutes : \\ {10}^8--{-}^{50 minutes}--> 2 \times {10}^8 --{-}^{100 minutes}-->4 \times {10}^8 --{-}^{150 minutes}-->8 \times {10}^8--{-}^{200 minutes}-->16 \times {10}^8--{-}^{250 minutes}--> 32 \times {10}^8. \\ 32 \times {10}^8--{-}^{300 minutes}-->64 \times {10}^8 cells. \\ Thus end of 300 minutes there will be 64 \times {10}^8 cells , it can be \\ expressed as 6.4 \times {10}^9 cells. \\ Option D is correct. \end{gathered}$$


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