I sincerely request the experts to solve the above diagram.

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I sincerely request the experts to solve the above diagram

Neha Sethi · Accepted Answer

Dear student
Since ∠COE and ∠BOG are consecutive  multiples of 10°So, Let ∠COE=10x and ∠BOG=10x+10°Since OA bisects ∠BOG∴∠AOB=∠AOG=12∠BOG=5x+5°Since OD bisects ∠COE∴∠COD=∠DOE=12∠COE=5xGiven: ∠BOC=∠COD4+90°=5x4+90°Since GE is a straight line∴∠BOG+∠BOC+∠COE=180°⇒10x+10°+5x4+90°+10x=180°⇒20x+5x4=80°⇒80x+5x=320°⇒85x=320°⇒x=32085°⇒x=6417°So,∠COE=10x=64017°∠BOG=10x+10=64017°+10°=81017°∠COD=∠DOE=12∠COE=6402×17=32017°∠AOB=∠AOG=12∠BOG=8102×17=40517°∠BOC=5x4+90°=54×6417°+90°=8017°+90°=161017°∠GOF=3∠BOG=3×81017°=243017°
and ,∠EOF=180°-∠GOF    {linear pair]⇒∠EOF=180°-243017°=63017°

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