If (1+i/1-i)3 - (1-i/1+i)3 = x+iy, then find (x,y)

(1+i/1-i)3 - (1-i/1+i)3    

RATIONALIZING DENOMINATORS

[ (1 + i)2 / (1 - i2 ) ]3  -  [ (1 - i)2 / (1 - i2 ) ]3

(2i/2)  -  (-2i/2)3 

i3   -  (-i)3

i3 + i3  = 2i3   =  2i(i2)  =  -2i

 

x + iy  = -2i

x =0

y = -2

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