If - 3 is root of quadratic equation 2xsquare +px-15=0 and quadratic equation p(x square +x) +k=0 has equal roots then find the value of k.?

Let f(x)=2x2+px-15 and g(x)=px2+px+k=0Since -3 is a root of f(x).So, f(-3)=02(-3)2+p(-3)-15=018-3p-15=03-3p=03(1-p)=01-p=0p=1    ...(1)Also,-3 is a root of g(x)So, g(-3)=0(1)(-3)2+(1)(-3)+k=0    using 19-3+k=06+k=0k=-6

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