If (a+b):(b+c):(c+a)=6:7:8, and (a+b+c)=14, then find the value of 'c'.
A)6
B)7
C)8
D)14
Let,
a + b = 6k...........................(1)
b + c = 7k...........................(2)
c + a = 8k...........................(3)
adding 1,2 and 3, we get
a + b + b + c + c + a = 6k + 7k + 8k
⇒2(a + b + c) = 21k
⇒(a + b + c) = 21k/2
but we have given a + b + c = 14
so, 21k/2 = 14
⇒k = 4/3
so a + b = 6 * 4/3 = 8
now c = (a + b + c) - (a + b) = 14 - 8 = 6