If a,b,c are in A.P. and a,b,d are in G.P. ,prove that a,a-b,d-c are in G.P.
a,b ,c are in ap
so 2b =a +c
and a,b ,d are in GP
b2 = ad
now a, a-b , d-c
a-b / a = d-c / a-b
(a-b)2 = a(d-c)
a2 +b2 -2ab = ad - ac
a2 + ad - a(a+c) = ad - ac
a2 - a2 - ac = -ac
ac =ac TRUE ......
hence a, a-d , d-c are in GP