If A + B = pi/4 prove that (cot A-1) (cot B-1) = 2
Given,
⇒ cot A cot B – 1 = cot B + cot A
⇒ cot A cot B – cot B – cot A = 1
⇒ cot A cot B – cot B – cot A + 1 = 1 + 1 (Adding 1 to both sides)
⇒ cot B (cot A – 1) – 1 (cot A – 1) = 2
⇒ (cot A – 1) (cot B – 1) = 2