If a + ib = (1 – i)(2 – 3i)(3 – i), find the value of a 2 + b 2 .

a+ib=1-i2-3i3-ia+ib=1-i2-3i3-i=1-i 2-3i 3-ia2+b2=12+12×22+-32×32+-12Squaring both sidesa2+b2=12+12×22+-32×32+-12a2+b2=2×13×10=260

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