If A is 3 × 3 invertible matrix, then show that for any scalar k (non-zero),kA is invertible and (kA)1 = 1/k.A-1. Share with your friends Share 3 Prasanta answered this We know that, kA-1=1kA×adjkA -----------(1) ⇒kA-1=1kA×kn-1×adj A , where n is the degree of the matrix (here 3) [since kA=knA] ⇒kA-1=1k3A×k2×adj A ⇒kA-1=1k×1A×adj A ⇒kA-1=1k×A-1 Hence Proved. 2 View Full Answer