If A is 3 × 3 invertible matrix, then show that for any scalar k (non-zero),kA is invertible and (kA)1 = 1/k.A-1.

We know that,

kA-1=1kA×adjkA -----------(1)

kA-1=1kA×kn-1×adj A , where n is the degree of the matrix (here 3)  [since kA=knA]

kA-1=1k3A×k2×adj A

kA-1=1k×1A×adj A

kA-1=1k×A-1

Hence Proved.
 

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