if a2 + b2 =1 , then find the value of 1+b+ia/1+b-ia

the given expression is: 1+b+ia1+b-ia 
multiplying by (b+ia) to the numerator and denominator:

1+b+ia1+b-ia×b+iab+ia=(1+b+ia)×(b+ia)b+b2-iab+ia+iab+a2=(1+b+ia)×(b+ia)a2+b2+b+ia=(1+b+ia)×(b+ia)1+b+ia  [given a2+b2=1]
=b+ia

hope this helps you

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