If cos tetha = 20/29 and sin tetha = 21/29 find the value of sin2 tetha + cos2 tetha

sin θ=2029 and cos θ=2129sin2θ+cos2θ=20292+21292                       =400+441841=1 ANS...

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= sin2theta + cos2theta
= ( 21/ 29 )2 + ( 20/29 )2
= ( 401/841 ) + ( 400/841)
= 841/841
= 1
 
  • 2
square of 21 will be 441...i am sorry  not 401
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