if cot theta= 1/ root 3, show that 1-cos square theta/ 2- sin square theta = 3/5.

let theta = x

cot x = 1/root3

cot x = cot 60

x = 60 degree

now,

1 - cos2x / 2 - sin2x = 3/5 

1 - (cos 60)2 / 2 - (sin 60)2 = 3/5

1 - (1/2)2 / 2 - (root3/2)2 = 3/5

1 - 1/4 / 2 - 3/4 = 3/5

(3/4) / (5/4) = 3/5

3/5 = 3/5

HENCE PROVED..........

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