If determinant p b c a q c =0 ,find the value of a/(p - a)+b/(q - b)+r/(r - c) ,(p!=a,q!=b,r!=c). a b rHelp me soon .Thank you Share with your friends Share 0 Ajanta Trivedi answered this the given determinant is: pbcaqcabr=0 applying R1→R1-R2 and R2→R2-R3(p-a)(b-q)00(q-b)(c-r)abr=0applying C1→C1p-a;C2→C2q-b;C3→C3r-c(p-a)(q-b)(r-c)1-1001-1a(p-a)bq-brr-c=0, since p≠a;q≠b and r≠c ⇒1-1001-1a(p-a)bq-brr-c=0now expanding the determinant:rr-c+bq-b-1.-ap-a=0ap-a+bq-b+rr-c=0 hope this helps you 0 View Full Answer