If f(x) = sqrt{ cos(sin x)} + sqrt{ sin(cos x)} then range of f(x) is

Dear student,
fx =cossinx+sincosx ...1for domain first term is always positive then sincosx0 then -π2xπ2 defferentiate eq1f'x = 12cossinx-sinsinx×cosx+12sincosxcoscosx×-sinxf'x =0,then x=0 f0 = 1+sin1f-π2 = fπ2=cos1so fmax = 1+sin1 ,fmin=cos1range  cos1fx1+sin1

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