if G is the centroid and I the incentre of the triangle with vertices A(-36,7) ,B(20,7) ,C(0,6) then find the value of GI?

_{1}, y

_{1}), (x

_{2}

_{, }y

_{2}) and (x

_{3}, y

_{3}) is (x

_{1}+x

_{2}+x

_{3}/3, y

_{1}+y

_{2}+y

_{3}/3) Therefore here co-ordinates of G is (-16/3, 2). If a, b and c are the lengths of opposite sides of vertices (x

_{1}, y

_{1}), (x

_{2, }y

_{2}) and (x

_{3}, y

_{3}) respectively then in-centre will be given by (ax

_{1}+bx

_{2}+cx

_{3}/a+b+c, ay

_{1}+by

_{2}+cy

_{3}/a+b+c). Here a=25, b=39, c=56 and a+b+c = 120. Therefore co-ordinates of I = (-1, 0). So, GI= (sqt of 205)/3.